Sample 1Medium
A graph of population density against time shows an S-shaped (sigmoid) curve levelling off at the carrying capacity K. For this population, r = 0.5 per year, K = 1000 individuals and the present size N = 200 individuals. Using the logistic equation dN/dt = rN[(K − N)/K], what is the present growth rate?
- A
80 individuals per year
- B
100 individuals per year
- C
160 individuals per year
- D
20 individuals per year
Show the answer
The answer is A.dN/dt = 0.5 × 200 × (1000 − 200)/1000 = 100 × 0.8 = 80 individuals per year. Logistic growth slows as N approaches K, giving the sigmoid curve.
- B.
This is rN, the exponential rate that ignores the limit set by K.
- C.
This doubles the correct value; the correct calculation gives 0.5 × 200 × 0.8 = 80.
- D.
This uses N/K (0.2) in place of (K − N)/K (0.8).
NCERT: Class 12 Biology, Chapter 11, 11.1
Sample 2NEET level
Match List I (interaction between two species) with List II (effect on the two species). List I: A. Mutualism B. Commensalism C. Amensalism D. Competition List II: I. (−, −) II. (+, 0) III. (−, 0) IV. (+, +) Choose the correct answer.
- A
A-IV, B-III, C-II, D-I
- B
A-II, B-IV, C-III, D-I
- C
A-IV, B-II, C-I, D-III
- D
A-IV, B-II, C-III, D-I
Show the answer
The answer is D.In mutualism both species benefit (+, +), and in commensalism one benefits while the other is unaffected (+, 0). In amensalism one is harmed and the other unaffected (−, 0), and in competition both lose (−, −).
- A.
Swaps commensalism and amensalism.
- B.
Swaps mutualism and commensalism.
- C.
Swaps amensalism and competition.
NCERT: Class 12 Biology, Chapter 11 (Organisms and Populations), Population interactions