Sample 1Medium
A molecule AB4 is sketched with its central atom A surrounded by five electron pairs pointing to the corners of a trigonal bipyramid: four are bond pairs to B atoms and one is a lone pair occupying an equatorial position. Which molecule has this arrangement, and what is its shape?
- A
CH4, tetrahedral
- B
ClF3, T-shaped
- C
SF4, see-saw
- D
XeF4, square planar
Show the answer
The answer is C.Four bond pairs and one lone pair (AB4E) give a trigonal bipyramidal arrangement of electron pairs. With the lone pair equatorial, the atoms form a see-saw shape, as in SF4.
- A.
CH4 has four bond pairs and no lone pair on carbon.
- B.
ClF3 has three bond pairs and two lone pairs, so it is AB3, not AB4.
- D.
XeF4 has six electron pairs (four bond pairs and two lone pairs) around Xe, not five.
NCERT: Class 11 Chemistry, Chapter 4
Sample 2NEET level
Match the molecules in List I with their shapes in List II. List I: A. SF4 B. ClF3 C. XeF4 D. BrF5 List II: I. Square pyramidal II. T-shape III. See-saw IV. Square planar
- A
A-II, B-III, C-I, D-IV
- B
A-III, B-II, C-I, D-IV
- C
A-IV, B-II, C-III, D-I
- D
A-III, B-II, C-IV, D-I
Show the answer
The answer is D.SF4 (four bond pairs, one lone pair) is see-saw and ClF3 (three bond pairs, two lone pairs) is T-shaped. XeF4 (four bond pairs, two lone pairs) is square planar and BrF5 (five bond pairs, one lone pair) is square pyramidal.
- A.
Swaps SF4 and ClF3, and swaps XeF4 and BrF5.
- B.
Swaps XeF4 (square planar) and BrF5 (square pyramidal).
- C.
SF4 is see-saw, not square planar, and XeF4 is not see-saw.
NCERT: Class 11 Chemistry, Unit 4 (Chemical Bonding and Molecular Structure), The Valence Shell Electron Pair Repulsion (VSEPR) Theory