NEET Chemistry · Classification of Elements and Periodicity in Properties

Periodic trends: radii, ionisation enthalpy, electron gain enthalpy

Taught in NCERT Class 11 Chemistry, Chapter 3: Classification of Elements and Periodicity in Properties.

2 verified questions: Easy 0 · Medium 2 · NEET level 0

Sample questions

Sample 1Medium

A graph of first ionisation enthalpy (y-axis) against atomic number (x-axis) for the elements lithium to neon shows a generally rising zig-zag line with two small dips: one at boron, which lies below beryllium, and one at oxygen, which lies below nitrogen. Which explanation of the two dips is correct?

  1. A

    B: its atom is larger than Be; O: its atom is larger than N

  2. B

    B: its 2p electron is more penetrating than a 2s electron; O: all four of its 2p electrons are unpaired

  3. C

    B: its 2p electron is less penetrating and better shielded than the 2s electrons of Be; O: two of its 2p electrons share one orbital and repel each other

  4. D

    B: it has a half-filled 2p subshell; O: it has a completely filled 2p subshell

Show the answer
The answer is C.

Boron's outer 2p electron is shielded by the 2s electrons and is held less tightly than beryllium's 2s electrons. In oxygen, one 2p orbital holds a pair whose mutual repulsion makes one of them easier to remove than an electron from nitrogen's half-filled 2p³.

  • A.

    Atomic radius decreases across a period, so B is smaller than Be and O is smaller than N.

  • B.

    A 2s electron penetrates closer to the nucleus than a 2p electron, and four electrons in three 2p orbitals cannot all be unpaired.

  • D.

    Boron has one 2p electron (2p¹) and oxygen has four (2p⁴); neither subshell is half-filled or full.

NCERT: Class 11 Chemistry, Chapter 3

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