NEET Chemistry · Redox Reactions and Electrochemistry

Conductance and Kohlrausch's law

Taught in NCERT Class 12 Chemistry, Chapter 2: Electrochemistry.

3 verified questions: Easy 0 · Medium 2 · NEET level 1

Sample questions

Sample 1Medium

A graph of molar conductivity Λm (y-axis) against √c (x-axis) for two electrolytes in water shows line P, nearly straight with a small negative slope, meeting the y-axis at a definite value, and curve Q, low and flat at higher √c but rising very steeply as √c approaches zero, so it cannot be traced to the axis. Which statement is correct?

  1. A

    Q is acetic acid, and its limiting molar conductivity is obtained from Kohlrausch's law

  2. B

    P is acetic acid, and its limiting molar conductivity is read from the intercept

  3. C

    Q is potassium chloride, a strong electrolyte

  4. D

    Q is acetic acid, and its limiting molar conductivity is found by extending curve Q to the y-axis

Show the answer
The answer is A.

A strong electrolyte such as KCl gives a nearly straight line whose intercept is Λ°m. A weak electrolyte such as acetic acid dissociates much more on dilution, so its curve rises steeply and Λ°m is found from Kohlrausch's law of independent migration of ions.

  • B.

    A nearly linear plot with a definite intercept belongs to a strong electrolyte such as KCl.

  • C.

    A strong electrolyte gives the nearly straight line P; the steep curve Q is typical of a weak electrolyte.

  • D.

    Because Q rises so steeply near zero concentration, it cannot be extended to the axis; Λ°m must come from Kohlrausch's law instead.

NCERT: Class 12 Chemistry, Chapter 2

Sample 2NEET level

At infinite dilution, the limiting molar conductivities of HCl, NaCl and CH3COONa are 425.9, 126.4 and 91.0 S cm² mol⁻¹ respectively. The limiting molar conductivity of acetic acid is

  1. A

    390.5 S cm² mol⁻¹

  2. B

    643.3 S cm² mol⁻¹

  3. C

    461.3 S cm² mol⁻¹

  4. D

    217.4 S cm² mol⁻¹

Show the answer
The answer is A.

By Kohlrausch's law, Λ°m(CH3COOH) = Λ°m(HCl) + Λ°m(CH3COONa) − Λ°m(NaCl). Λ°m(CH3COOH) = 425.9 + 91.0 − 126.4 = 390.5 S cm² mol⁻¹.

  • B.

    Adds all three values instead of subtracting NaCl.

  • C.

    Subtracts CH3COONa and adds NaCl, the reverse combination.

  • D.

    Adds only NaCl and CH3COONa, ignoring HCl.

NCERT: Class 12 Chemistry, Unit 2 (Electrochemistry), Conductance of Electrolytic Solutions: Applications of Kohlrausch law

Practise Conductance and Kohlrausch's law

Practice at the level you choose, with the answer after every question; timed tests with the answers when you submit. Every question is verified against NCERT first.

Sign in to practise

More in Redox Reactions and Electrochemistry