Sample 1Medium
How many oxygen atoms are present in 4.4 g of carbon dioxide? (C = 12 u, O = 16 u, N_A = 6.022 × 10^23 mol^-1)
- A
1.204 × 10^23
- B
6.022 × 10^22
- C
2.409 × 10^23
- D
3.011 × 10^22
Show the answer
The answer is A.Molar mass of CO2 is 44 g mol^-1, so 4.4 g is 0.1 mol of CO2. Each molecule has two O atoms, giving 0.2 mol O atoms = 0.2 × 6.022 × 10^23 = 1.204 × 10^23 atoms.
- B.
This is the number of CO2 molecules (0.1 mol), not oxygen atoms.
- C.
This counts four O atoms per molecule, double the true number.
- D.
This is half the number of CO2 molecules; it neither counts molecules nor atoms correctly.
NCERT: Class 11 Chemistry, Chapter 1, 1.8
Sample 2NEET level
The number of molecules present in 4.4 g of carbon dioxide (molar mass 44 g mol⁻¹; NA = 6.022 × 10²³ mol⁻¹) is
- A
6.022 × 10²³
- B
6.022 × 10²²
- C
1.2044 × 10²³
- D
3.011 × 10²²
Show the answer
The answer is B.Moles of CO2 = 4.4 g / 44 g mol⁻¹ = 0.1 mol. Number of molecules = 0.1 mol × 6.022 × 10²³ mol⁻¹ = 6.022 × 10²² molecules.
- A.
This is the number in one full mole (44 g), not 0.1 mol.
- C.
This is twice the correct value, as if 0.2 mol were present.
- D.
This is half the correct value, as if 0.05 mol were present.
NCERT: Class 11 Chemistry, Unit 1 (Some Basic Concepts of Chemistry), Mole Concept and Molar Masses