Sample 1Medium
A thin biconvex lens of refractive index 1.5 has both radii of curvature 20 cm. Its focal length when immersed in a liquid of refractive index 1.25 is
- A
20 cm
- B
25 cm
- C
50 cm
- D
40 cm
Show the answer
The answer is C.In the liquid, 1/f = (1.5/1.25 − 1)(1/20 + 1/20) = 0.2 × 0.1 = 0.02 cm⁻¹, so f = 50 cm.
- A.
20 cm is the focal length in air.
- B.
25 cm only multiplies the air focal length by 1.25.
- D.
40 cm uses (1.5 − 1.25) instead of (1.5/1.25 − 1) in the lens maker's formula.
NCERT: Class 12 Physics, Chapter 9, Refraction at spherical surfaces and by lenses (lens maker's formula)
Sample 2NEET level
A thin biconvex lens of glass of refractive index 1.5 has both radii of curvature equal to 20 cm. It is completely immersed in water of refractive index 4/3. The focal length of the lens in water is
- A
8.9 cm
- B
20 cm
- C
60 cm
- D
80 cm
Show the answer
The answer is D.By the lens maker's formula, 1/f = (n₂₁ − 1)(1/R₁ − 1/R₂), where n₂₁ = 1.5 ÷ (4/3) = 9/8 is the index of glass relative to water. So 1/f = (1/8)(2/20) = 1/80 and f = 80 cm, four times the 20 cm focal length in air.
- A.
Uses n₂₁ = 9/8 but leaves out the −1: 1/f = (9/8)(1/10).
- B.
20 cm is the focal length in air, with n₂₁ = 1.5.
- C.
Subtracts the indices, 1.5 − 4/3 = 1/6, instead of taking their ratio.
NCERT: Class 12 Physics, Chapter 9 (Ray Optics and Optical Instruments), Refraction by a lens: lens maker's formula