NEET Physics · Properties of Solids and Liquids

Heat transfer: conduction, convection and radiation

Taught in NCERT Class 11 Physics, Chapter 10: Thermal Properties of Matter.

1 verified question: Easy 0 · Medium 1 · NEET level 0

Sample questions

Sample 1Medium

Two rods of equal length and equal cross-section are joined end to end and lagged along their sides. Rod 1 has thermal conductivity K and its free end is held at 100 °C; rod 2 has conductivity 2K and its free end is held at 0 °C. In the steady state, what is the temperature of the junction?

  1. A

    50 °C

  2. B

    66.7 °C

  3. C

    33.3 °C

  4. D

    25 °C

Show the answer
The answer is C.

In the steady state the heat current is the same in both rods: K(100 − T) = 2K(T − 0), so T = 100/3 ≈ 33.3 °C.

  • A.

    50 °C holds only if the two conductivities are equal.

  • B.

    66.7 °C would result if the better conductor were at the hot end.

  • D.

    25 °C does not satisfy K(100 − T) = 2K T.

NCERT: Class 11 Physics, Chapter 10

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