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NEET Physics · Kinematics

Projectile motion

Taught in NCERT Class 11 Physics, Chapter 3: Motion in a Plane.

3 verified questions: Easy 0 · Medium 2 · NEET level 1

Sample questions

Sample 1Medium

A figure shows a ball projected from level ground with speed 20 m/s at 30° above the horizontal; it follows a parabola and lands back on the same level. Take g = 10 m/s². What is the maximum height of the parabola above the ground?

  1. A

    10 m

  2. B

    5 m

  3. C

    20 m

  4. D

    2.5 m

Show the answer
The answer is B.

Maximum height H = u² sin²θ / 2g = (400 × 0.25) / 20 = 5 m.

  • A.

    10 m drops the factor 2 in the denominator of u² sin²θ / 2g.

  • C.

    20 m is u²/2g, the height for a vertical throw, not for 30°.

  • D.

    2.5 m uses sin²θ twice or halves the correct result; it is not u² sin²θ / 2g.

NCERT: Class 11 Physics, Chapter 3

Sample 2NEET level

A ball is projected from level ground with a speed of 20 m/s at an angle of 60° to the horizontal. Taking g = 10 m/s², the maximum height reached by the ball is

  1. A

    5 m

  2. B

    15 m

  3. C

    20 m

  4. D

    30 m

Show the answer
The answer is B.

H = u² sin²θ / 2g = (400 × 0.75) / 20 = 15 m. Only the vertical component u sinθ = 10√3 m/s decides the height.

  • A.

    Uses sin²30° = 0.25 instead of sin²60° = 0.75.

  • C.

    Uses u²/2g, the height for a vertical throw, ignoring the angle.

  • D.

    Drops the factor 2 in the denominator: u² sin²θ / g.

NCERT: Class 11 Physics, Chapter 3 (Motion in a Plane), Projectile motion

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