Sample 1Medium
A particle moves with constant speed on a circle of radius 2 m and completes one revolution in π s. The magnitude of its acceleration is
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The answer is D.
ω = 2π/T = 2π/π = 2 rad s⁻¹. The centripetal acceleration is a = ω²r = 4 × 2 = 8 m s⁻².
- A.
4 m s⁻¹ is the particle's speed, not its acceleration.
- B.
16 m s⁻² is v² without dividing by the radius.
- C.
2 m s⁻² is ω²r with ω taken as 1 rad s⁻¹ instead of 2 rad s⁻¹.
NCERT: Class 11 Physics, Chapter 3, Uniform circular motion