Sample 1Medium
A graph for a block oscillating on a spring in SHM has displacement x on the horizontal axis, from −A to +A. Two parabolas are drawn: potential energy, zero at x = 0 and maximum at ±A, and kinetic energy, maximum at x = 0 and zero at ±A. A horizontal line marks the total energy E. At x = A/2, what fraction of E is kinetic energy?
- A
1/2
- B
1/4
- C
3/4
- D
1/3
Show the answer
The answer is C.Potential energy = ½kx² = ¼ × ½kA² = E/4 at x = A/2. Since the total energy is constant, KE = E − E/4 = 3E/4.
- A.
The two energies are equal at x = A/√2, not A/2.
- B.
1/4 is the potential energy fraction at A/2.
- D.
1/3 does not follow from ½kx² at x = A/2.
NCERT: Class 11 Physics, Chapter 13
Sample 2NEET level
A block of mass 0.5 kg attached to a spring of force constant 200 N/m oscillates on a smooth horizontal surface with an amplitude of 0.1 m. The maximum speed of the block is
- A
1.41 m/s
- B
2 m/s
- C
2.83 m/s
- D
40 m/s
Show the answer
The answer is B.ω = √(k/m) = √(200/0.5) = 20 rad/s, so v_max = ωA = 20 × 0.1 = 2 m/s. Check by energy: ½kA² = 1 J = ½mv_max² gives v_max = 2 m/s.
- A.
Equates ½kA² to mv² instead of ½mv².
- C.
Equates kA² to ½mv², dropping the ½ on the spring's side.
- D.
Takes ω = k/m = 400 rad/s, forgetting the square root.
NCERT: Class 11 Physics, Chapter 13 (Oscillations), Energy in simple harmonic motion