Sample 1Medium
A particle executes simple harmonic motion given by x = 0.05 cos(10t + π/3), with x in metres and t in seconds. Its speed when its displacement is 0.03 m is
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The answer is C.
Speed v = ω√(A² − x²) = 10 × √(0.0025 − 0.0009) = 10 × 0.04 = 0.4 m s⁻¹.
- A.
0.5 m s⁻¹ is the maximum speed ωA, reached only at x = 0.
- B.
0.3 m s⁻¹ is ωx, which is not the speed formula.
- D.
0.16 m s⁻¹ is ω²(A² − x²); the speed is ω√(A² − x²).
NCERT: Class 11 Physics, Chapter 13, Simple harmonic motion and Velocity in SHM